Math, asked by sameersharma20116, 1 year ago

The sum of the area of two square field is 468m2. If the diffrence of their perimeter is 24m, find the sides of the two square.

Answers

Answered by originaljustice
0
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sameersharma20116: 468m upper me square 2 hai
Answered by jayantic160
3

Let us say that the sides of the two squares are 'a' and 'b'


Sum of their areas = a^2 + b^2 = 468


Difference of their perimeters = 4a - 4b = 24


=> a - b = 6


=> a = b + 6


So, we get the equation


(b + 6)^2 + b^2 = 468


=> 2b^2 + 12b + 36 = 468


=> b^2 + 6b - 216 = 0


=> b = 12


=> a = 18


The sides of the two squares are 12 and 18.


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sameersharma20116: 468m square 2 hai
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