Question

the sum of the area of two squares is 452 square if the difference of their perimeter is 8 find sides of the two square​

Answer 1

Answer:

here is the answer for question.

Step-by-step explanation:

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Answer 2

Answer:

The sides of the square are 14 and 16  

Step-by-step explanation:

• Let the side of 1st square is $x$. The area of the square is given by $x^{2}$
• Let the side of 2nd square is $y$.The area of square is given by $y^{2}$
• The sum of the area of 2 squares is 452. This can be represented as

        $x^{2} +y^{2}=452\ \ \ \ \ \ \ \ \ \ \ .....eq 1$

• The perimeter of 1st square =$4x$
• The perimeter of 2nd square =$4y$
• Difference of the perimeter is 8 and can be represented by

        $4x-4y=8\\x-y=2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \....eq 2$

• Put value of x from eq 2 into 1

        $(2+y)^{2} +y^{2}=452\\\\4+y^{2} +4y+y^2=452\\2y^2+4y-448=0\\y^2+2y-224=0$

• On solving the root, y=14 and -16. since side cant be negative. y=14
• Put the value of y in eq2, $x=16$

conclusion:

The sides of the square are 14 and 16