Question

the sum of the area of twosquares is850 if differance of their perimetersis40 find the sides of the two squares​

Answer 1

Answer:

Hey Mate here is your solution ❤❤

Step-by-step explanation:

Perimeter of a square = 4L since all the sides are equal.

Let the smaller square be of side x.

Since the difference in perimeter = 40 m then each side of the larger square is greater by:

= 40/4 = 10 m

The sides of the larger square will be (x + 10) m

Their areas are as follows :

x² + (x + 10)² = 850

Expanding this we have :

x² + x² + 20x + 100 = 850

Collecting the like terms together we have :

2x² + 20x - 750 = 0

Divide all through by 2 we have :

x² + 10x - 375 = 0

The roots are +25 and - 15

We expand the equation :

x² + 25x - 15x - 375 = 0

x(x + 25) - 15(x + 25) = 0

(x - 15)(x + 25) = 0

The value of x will be :

x = 15 or - 25

We take the positive value of x since measurements are normally positive.

The side of the bigger side is :

15 + 10 = 25

Smaller square : 15 by 15

Bigger square = 25 by 25

thx you