Question

the sum of the areas of 2squares is 400sqm if difference between their perimeter is 16m find the sides of 2 squares

Answer 1

Answer:

the answers are 8, 24

Step-by-step explanation:

• sum of area of the square =400

sum of 1 side of bot square =

$\sqrt{400} = 20$

sum of their perimeter =20×4=80

difference between the perimeters =16

let their perimeter be X,X+16

so X+X+16=80

=2x=80-16

x=

$\frac{64}{2}$

which is equal to 32 so x+16=48

so their perimeter are x/4=32/4=8

and(x+16)/4=48/4=24