The sum of the areas of two square is 640m sq . If the difference of their perimeter is 128 sq , find the sides
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Answer:
Step-by-step explanation:
Let the radius be x and y for different square
Atq.
X^2+y^2=640m^2 (sum of areas of square)
(i)x^2+y^2=640m^2
(ii)4x+4y=128 m
》4(x+y)=4(32)
Cancelling 4 in both side
New eq
X+y=32
Y=32-x
Putting value in eq (i)
X^2+(32-x)^2=640
On solving
X^2+1024+x^2-64x=640
2x^2-64x+1024-640=0
2x^2-64x+384=0
2(x^2-32x+192)=0
X^2-32x+192=0
By using splitting the middle term
X^2-24x-8x+192=0
X(x-24) -8(x-24)=0
(X-24)(x-8)=0
X=24 or x=8
If x is taken 24 then other side of triangle will 8 by using (ii)eq or if x is taken 8 then other side of triangle will be 24 m
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