The sum of the areas of two squares is 640m^2.if the difference in their perimeters be 64m,find the sides of the two squares
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let side of bothb be x &y.
so according to que..
x^2+y^2=640...(1)
4(x-y)=64
(x-y)^2=16^2.=x^2+y^2 2xy=256
by putting. value(1)
we got..
640-2xy=256...
so xy= 192....
by solving we got
x=24 and y=8
so according to que..
x^2+y^2=640...(1)
4(x-y)=64
(x-y)^2=16^2.=x^2+y^2 2xy=256
by putting. value(1)
we got..
640-2xy=256...
so xy= 192....
by solving we got
x=24 and y=8
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