The sum of the areas of two squares is 640m². If the difference between their perimeters is 64m
then find sides of the square,
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Answer:sides of the square are 24,8.
Step-by-step explanation:Let the two squares be A and B
Side length of square A is x and side length of square B is y
Area of square=s*s
Perimeter of square =4s
Areas is x^2+y^2=640
Perimeters is 4x-4y=64
By substituting we get a quadratic equation
y^2+16y-192=0
Roots are y=8,y=-24.
By substituting in any one equation we get
x=24.
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Answer:
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