Question

The sum of the areas of two squares is 640m². If the difference between their perimeters is 64m
then find sides of the square,
​

Answer 1

Answer:sides of the square are 24,8.

Step-by-step explanation:Let the two squares be A and B

Side length of square A is x and side length of square B is y

Area of square=s*s

Perimeter of square =4s

Areas is x^2+y^2=640

Perimeters is 4x-4y=64

By substituting we get a quadratic equation

y^2+16y-192=0

Roots are y=8,y=-24.

By substituting in any one equation we get

x=24.

Answer 2

Answer:

see below answer in the attachment!

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Step-by-step explanation: