Question

The sum of the areas of two squares is 640m².The difference between their perimeter is 64m.Find lenght of sides of both squares

Answer 1

let the l be x and x
both square area is 640
x+x =640
2x=640
320
one is less in perimeter by 64 ,so 64 - 320 = 256 is the one of area .
another is 384 in area .
l = 16 of both side ,as we know that all sides are same of square .

Answer 2

Step-by-step explanation:

Let the sides of the two squares be x and y [x > y]

Perimeter = 4 x side

                = 4x - 4y = 64

                = x - y = 16

                = x = 16 + y

x^2 + y^2 = 640

[16 + y]^2 + y^2 = 640

y^2 + 32y + 256 + y^2 = 640

2y^2 + 32y + 256 - 640 = 0

2y^2 + 32y - 384 = 0

y^2 + 16y - 192 = 0/2 = 0

y^2 + 24y - 8y - 192 = 0

y [y+24] -8 [y+24] = 0

y = -24 [rejected]         y = 8

   = y = 8m

  = x = y + 16 = 8 + 16 = 24m