the sum of the arithmetic sequence 51+52+53......+70
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Answer:
the sum of the arithmetic sequence is 1210
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Answer:
a1 = 51
a2 = 52
an = 70
d = a2-a1
= 52-51
= 1
an = a+(n-1)d
70 = 51 +(n-1)1
70-51 = n-1
19 = n-1
n = 19+1
n=20
Sn = n/2[2a+(n-1)d]
S20 = 20/2[2×51 +(20-1)1]
= 10 [102 +19]
= 10×121
= 1210
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