Math, asked by HimangiSingh8561, 1 year ago

The sum of the base and height of solid cylinder is 37m if the totalsurface area of cyli







nder is 1628msq find volume

Answers

Answered by rustyattacker03629
1

let \: radius \: be \: r  \: and \: height \: be \: h \\ \\  but \: the \: sum \: of \: radius \: and \: height \: is \: 37m \\  \\ total \: surface \: area \: of \: cylinder = 1628 {m}^{2}  \\  =  > 2\pi \: r(r + h) = 1628 \\ \\  =  > 2 \times  \frac{22}{7} \times r(37) = 1628 \\  \\  =  > r =  \frac{1628 \times 7}{44 \times 37}  \\  \\  =  > r = 7m \\  \\ so \:  \: radius \: is \: 7m \\ then \: height = \\ =  > r + h = 37 \\  =  > 7 + h = 37 \\  =  > h = 37 - 7 \\  =  > h = 30m \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: acc. \: to \: ques. -  -  \\ volume \: of \: cylinder = \pi \:  {r}^{2}h \\  =  \frac{22}{7} \times 7 \times 7 \times 30 \\  \\  = 4620 {m}^{3}
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