Math, asked by HimangiSingh8561, 11 months ago

The sum of the base and height of solid cylinder is 37m if the totalsurface area of cyli







nder is 1628msq find volume

Answers

Answered by rustyattacker03629
1

let \: radius \: be \: r  \: and \: height \: be \: h \\ \\  but \: the \: sum \: of \: radius \: and \: height \: is \: 37m \\  \\ total \: surface \: area \: of \: cylinder = 1628 {m}^{2}  \\  =  > 2\pi \: r(r + h) = 1628 \\ \\  =  > 2 \times  \frac{22}{7} \times r(37) = 1628 \\  \\  =  > r =  \frac{1628 \times 7}{44 \times 37}  \\  \\  =  > r = 7m \\  \\ so \:  \: radius \: is \: 7m \\ then \: height = \\ =  > r + h = 37 \\  =  > 7 + h = 37 \\  =  > h = 37 - 7 \\  =  > h = 30m \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: acc. \: to \: ques. -  -  \\ volume \: of \: cylinder = \pi \:  {r}^{2}h \\  =  \frac{22}{7} \times 7 \times 7 \times 30 \\  \\  = 4620 {m}^{3}
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