Question

The sum of the cube of first four natural number Is the square of

Answer 1

Step-by-step explanation:

It seems that the sum is always square, but what is even more remarkable is that the sum of the first n cubes, 13+23+... + n 3 = ( n ( n +1)/2)2, which is the square of the n th triangle number. For example, 13+23+... +103=(10×11/2)2=552 = 3025.

Answer 2

Answer:

The sum of the cube of first four natural number Is the square of ten

Step-by-step explanation:

We know that sum of cubes of first n natural numbers is = (n(n+1)/2)²

                                        for first four natural numbers = (4(4+1)/2)²

                                                                                         = 100 = 10²