The sum of the cubes of first n natural number = ……….
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It seems that the sum is always square, but what is even more remarkable is that the sum of the first n cubes, 13+23+... + n 3 = ( n ( n +1)/2)2, which is the square of the n th triangle number.
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We know that sum of cubes of first n natural numbers is = (n(n+1)/2)².
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