The sum of the cubes of the first n natural numbers is equal to the square of their sum. Using this property, what is the sum of the cubes of the first 10 natural numbers? Show the working
Answers
Answered by
2
Answer:
3025
Step-by-step explanation:
1+2+3+4+5+6+7+8+9+10=55
55^2=3025
Answered by
0
Answer:
Property 3 The sum of the cubes of first n natural numbers is equal to the square of their sum. That is 1^3 + 2^3 + 3^3 +.
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