Math, asked by himakshikoloti, 1 month ago

The sum of the cubes of the first n natural numbers is equal to the square of their sum. Using this property, what is the sum of the cubes of the first 10 natural numbers? Show the working

Answers

Answered by swayamkrishna1
2

Answer:

3025

Step-by-step explanation:

1+2+3+4+5+6+7+8+9+10=55

55^2=3025

Answered by baramdebchoudhury
0

Answer:

Property 3 The sum of the cubes of first n natural numbers is equal to the square of their sum. That is 1^3 + 2^3 + 3^3 +.

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