the sum of the cubes of three numbers which are in ratio 1:2:3 is 7776 find the numbers
Answers
Answered by
54
Given sum of cubes = 7776
(a)^3 + (2a)^3 + (3a)^3 = 7776
a^3 + 8a^3 + 27a^3 = 7776
36a^3 = 7776
a^3 = 216
a = 6
So the three numbers will be 6,12,18
(a)^3 + (2a)^3 + (3a)^3 = 7776
a^3 + 8a^3 + 27a^3 = 7776
36a^3 = 7776
a^3 = 216
a = 6
So the three numbers will be 6,12,18
Answered by
84
QUESTION ---- the sum of the cubes of three numbers which are in ratio 1:2:3 is 7776 find the numbers
ANSWER
___________________________
Let the numbers be x, 2x and 3x
It is given that sum of there cubes = 7776
So, Equation will be
x^3 + (2x) ^3 + (3x) ^3 = 7776
x^3 + 8x^3 + 27x^3 = 7776
=> 36x^3 = 7776
=> x^3 = 7776 / 36
=> x^3 = 216
=> x = 3√216
=> x = 6
___________________________
ANSWER :
First Number = 6
Second Number = 12
Third Number = 18
______________________
HOPE IT HELPS :):):):):)
ANSWER
___________________________
Let the numbers be x, 2x and 3x
It is given that sum of there cubes = 7776
So, Equation will be
x^3 + (2x) ^3 + (3x) ^3 = 7776
x^3 + 8x^3 + 27x^3 = 7776
=> 36x^3 = 7776
=> x^3 = 7776 / 36
=> x^3 = 216
=> x = 3√216
=> x = 6
___________________________
ANSWER :
First Number = 6
Second Number = 12
Third Number = 18
______________________
HOPE IT HELPS :):):):):)
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