The sum of the cubes of two numbers is 793. The sum
of the numbers is 13, then the difference of the two
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Answer:
Correct Option: C
Let the numbers be a and b where a > b.
According to the question,
a3 + b3 = 793
and a + b = 13
∴ (a + b)3 = a3 + b3 + 3ab (a + b)
⇒ (13)3 = 793 + 3ab ×13
⇒ 2197 = 793 + 39ab
⇒ 39ab = 2197 – 793 = 1404
⇒ ab =
1404
= 36
39
∴ (a + b)2 = (a + b)2 – 4ab
= (3)2 = 4 × 36
= 169 – 144 = 25
⇒ a – b = √25 = 5
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