Question

The sum of the degit of a 2_digit number is 12. If the new number formed by reversing the digit is greater then the original number by 54, find the original number

Answer 1

Let take 2digits as a and b , a+b = 12.... equation 1

54+(10a+b)=(10b+a)

9a-9b= (-54)

a-b= (-6).... equation 2

adding equation 1 and 2

a+b= 12

a-b = (-6)

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2a=6

a=3

so b=9

39+54=93

Original number = 39

Reversed number = 93

tq. hope u understand.