Question

the sum of the digit in a two digit number is 9. the number obtained by interchanging the digit exceeds the original number by 27. find the two digit number.
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Answer 1

Answer:

Step-by-step explanation:

First Number at unit place is is x and tens place is y

So original number is 10y+x

After interchnaging digits number will be 10x+y

number obtained by interchanging the digits exceed the given number by 27

10y+x+27 = 10x+y

10y-y+x-10+27=0

9y-9x+27=0

9 (3y-3x+9=0)

3y-3x+9=0---------(1)

The sum of digit of a 2digit number is 9

x+y= 9---------------(2)

can be solved further by any method i will do by elimination method

Multiplyinjg eq 1 by 1 3y-3x=9

Multiplyinjg eq 2 by 3 3y+3x=27

- - -

- 6x = -18

x= -18/-6

x= 3

Subtituting value in eq 1

x+y=9

3+y=9

y=6