Math, asked by GouravSinghRathore, 1 year ago

the sum of the digit in a two digit number is 9. the number obtained by interchanging the digit exceeds the original number by 27. find the two digit number.​

Answers

Answered by ss2749512
11

Answer: let the unit digit be x

Then the tens digit be 9-x

Original no.= 10(9-x) +1(x)

=90-10x+x=90-9x

Reserve no=10(x) +1(9-x)

=10x+9-x=9x+9

A. T. Q

90-9x=9x+9+27

-9x-9x=36-90

-18x= -54

X= - _54_

18

X=3

Original no =10(9-3) +1(3)

=60+3=6e



Answered by afsanasyd4
1

Answer:

the original two - digit number is 36.

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