Question

The sum of the digit number is 11. 63is subtract with the number and the data number of the digit is get interchanged what is answer 32 52 either 92

Answer 1

Answer:

The original number is 92

Step-by-step explanation:

Let the digit in the one's place be "x"

Let the digit in the ten's place be "y"

The number therefore = 10y + x

The sum of digits is 11,

=> x + y = 11 ........(i)

When 63 is subtracted from the number, we get:

10y + x - 63

According to the problem, when this is done, the digits get interchanged.

=> 10y + x - 63 = 10x + y

=> 9y - 9x = 63

=> y - x = 7

=> -x + y = 7 ..........(ii)

Adding (i) and (ii), we get:

2y = 18

=> y = 9

Using (i), we get:

x + 9 = 11

=> x = 2

Now,

Digit in the one's place is "x"

Digit in the ten's place is "y"

=> The number is 92

The original number therefore is 92

Verification:

Original number = 92

Original number less 63 = 92 - 63 = 29

29 is the number obtained on interchanging the digits of 92

(Thus, verified)