the sum of the digit of 2 digit number is 8 the number obtained by interchanging the digits exceeds the given number by 18 find the given numbers
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Let the given number be 10x+y
according to the question;
x+y= 8 -------(eq1)
now , by interchanging the digits of the no. we get 10y+x
10y+x=10x+y+18
9y-9x=18
y-x=2
y=2+x
On substituting it eq 1
we get x=3
and y=5
therefore the given number is 35
I hope this helped u ☺️
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