the sum of the digit of 2 ind the original number is 9. the number formed by revising the digits is 45 more than the original number. find the original number
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Answer:
x+y=9
10x+y+45=10y+x
9x-9y=-45
x-y=5
x+y=9
x-y=5
2y=14
y=7
x=2
Number =27
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