The sum of the digit of a 2 digit no is 12 if the new no formed by reversing the digit is greater then the original no by 54 find the original no
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Step-by-step explanation:
Let the numbers of the two digit number be x and y.
Then the two digit number is 10x+y.
It is given that x + y = 12 ……….(1)
It is also given that the new number formed by reversing the digits is greater than the original number by 54.
So,
10y + x –(10x + y) = 54
⇒ 9y – 9x = 54
⇒ y – x = 6………..(2)
On adding equation (1) and (2) we get,
⇒ x + y + y – x = 18
⇒ 2y = 18
⇒ y = 9
putting the value of y in equation (1) we get,
⇒ x + 9 = 12
⇒ x = 3
We have assumed the number is 10x +y.
On putting the value of x and y we get 10(3) + 9 =39.
Hence the number is 39.
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