Question

The sum of the digit of a 2 digit number is 10. If the number formed by the reversing the digit is greater than the original number by 36 find the original number

Answer 1

here is your answer...

Answer 2

Answer: The digits are 3 and 7. The first number is 37 and the second number is 73

Step-by-step explanation:

Let the two digit number be xy, where x occupies 10s place value and y occupies 1s place value,

then the equation would be 10x +y

It is given x + y =10

Also if the digits are reversed ie it becomes yx,

then the equation is 10y + x since y has 10s place value and x has 1s place value

It is given 10y + x = 36 more than the first case ie 36 + 10x + y

so 10y + x = 36+10x+y

Simplifying we will get

9x - 9y = -36

It is given x+y = 10

Solving 9x-9y= -36

              x + y = 10

Multiply x + y = 10 by 9

9x-9y = -36

9x+9y=90

18x = 54

x = 3

x+y =10

3+y=10

y=7

In the first case the number is 10x + y, 10(3) + 7 = 37

In the 2nd case it is 36 more than the first ie 36 + 37 = 73

Verify for 2nd case 36+10x+y  = 36+10(3)+7  = 36+37 = 73