The sum of the digit of a 2-digit number is 8 . If the digits of the number are reversed , the number remains the same. Find the number.
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3
44 is the answer of this question
komal1957:
Plz send solution of this answer
Answered by
7
here Ur ur answer buddy......
let the tens digit be x and the ones digit be y
original number=10x+y
by given data....,
x+y=8
10x+y=10y+x
9x-9y=0
x-y=0
=>x+y=8
=>x-y=0
2x=8
(x=4)
x+y=8
4+y=8
y=4
so the digit is
10x+y=10(4)+4=44
hope it helps
let the tens digit be x and the ones digit be y
original number=10x+y
by given data....,
x+y=8
10x+y=10y+x
9x-9y=0
x-y=0
=>x+y=8
=>x-y=0
2x=8
(x=4)
x+y=8
4+y=8
y=4
so the digit is
10x+y=10(4)+4=44
hope it helps
i think helps
if u can ,.........make me as brainliest
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