The sum of the digit of a 2-digit number is 9. if the number by reversing the digits is 27 than the original number,find the original number.
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the answer is equal to 63 or 36
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Answer:
Step-by-step explanation:
Let us assume x is a tenth place digit and y is unit place digit
Therefore the two digit no. = 10x + y and the reversed = 10y +x
Given,
Y =2 x ----------1
Also given
10x + y + 27 = 10y +x
9y - 9x =27
Y-x = 3
Substitute the equation equation 1 from equation 2
2= 2x - x = 3
Therefore y = 2x = 2*3 = 6
The two digit number = 10x +y =10 * 3 +6 = 36
After add 27 = 36+27 = 63 (reversed of 36)
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