Question

the sum of the digit of a 2-digits no. is 11.The no. obtained by interchanging the digit exceeds the original no. by 27.Find the no.

Answer 1

Let 10s digit be x and 1s place digit be y,

Then.... x + y = 11 (a)and original no. = 10x+y

ATQ,

x + 10y = 10x + y +27 (b)

Therfore, x = 11 - y

11-y+10y=110-10y+y+27
18y=72
Y=4

X+4 = 11...x=4

Therefore the no. = 10.4 + 7
40+7
47...answer