Math, asked by Zaware, 1 year ago

the sum of the digit of a number consisting of three digits is 12 the middle digits is equal to half the sum of the other two if the order of the digits is reverse the number is diminished by 198 find the number. ​

Answers

Answered by shameemamk
41

Answer: 543

Step-by-step explanation:

Let a be the hundreds digit, b be the tens digit and c be the ones digit

Then a+b+c=12

b=12-a-c -------(1)

b=(a+c)/2 --------(2)

100a+10b+c-198=100c+10b+a

99a-99c = 198

99(a-c) = 198

a-c = 2----(3)

From (1) and (2), 12-a-c=(a+c)/2

24-2a-2c=a+c

3a+3c=24

a+c=8-----(4)

(3) + (4) --->

2a = 10

a = 5

(4)-(3)

2c=6

c=3

From (2), b=(5+3)/2 = 4

The number is 543

Similar questions