Question

The sum of the digit of a three digit number is 16. If the ten's digit of the number is 3 times the unit's digit is one – fourth of the hundredth digit, then what is the number ?​

Answer 1

Answer:

$\huge\underline\bold {Answer:}$

Let the hundredth’s digit be x.

Then, unit’s digit

= x/4, ten’s digit = 3x/4

Given, x + x/4 + 3x/4 = 16

$= > \frac{4x + x + 3x}{4} = 16$

=> 2x = 16

=> x = 8

Therefore ten’s digit

= 3 × 8/4 = 6,

unit’s digit = 8/4 = 2

Therefore required number

= 100 × 8 + 10 × 6 + 2

= 800 + 60 + 2

= 862.

Answer 2

Answer:

Let the number be ABC

A+B+C = 16

B = 3C

C=A/4

B = 3A/4

A + 3A/4 + A/4 = 16

2A = 16

A = 8

B = 24/4 = 6

C = 8/4 = 2

Thus, the number is 862

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