Question

The sum of the digit of a three digit number is 16. If the ten's digit of the number is 3 times the unit's digit is one – fourth of the hundredth digit, then what is the number ?​

Answer 1

$\huge\underline\bold {Answer:}$

Let the hundredth’s digit be x.

Then, unit’s digit

= x/4, ten’s digit = 3x/4

Given, x + x/4 + 3x/4 = 16

$= > \frac{4x + x + 3x}{4} = 16$

=> 2x = 16

=> x = 8

Therefore ten’s digit

= 3 × 8/4 = 6,

unit’s digit = 8/4 = 2

Therefore required number

= 100 × 8 + 10 × 6 + 2

= 800 + 60 + 2

= 862.

Answer 2

LETS TAKE 3 DIGITS AS - A , B AND C

A = UNIT DIGIT

B = TENS DIGIT

C = HUNDREDTH DIGIT

SOL:-

THE TEN'S DIGIT IS THRICE THE UNIT DIGIT..

B = 3A ...(1)

THE HUNDREDTH DIGIT IS TWICE THE UNIT DIGIT..

C = 2A ...(2)

THE SUM OF THREE DIGITS IS 12

A + B + C = 12

USING EQN 1 AND 2...WE GET

A + 3A +2A = 12

6A = 12

A = 12/6

A = 2

THEN ,

B = 3A = 3 × 2 =6

C = 2A = 2 × 2 = 4

PUTTING THESE VALUES IN THREE DIGIT NO..

CBA

= 462

IS THE THREE DIGIT NUMBER..