Question

the sum of the digit of a two digit no is 12.if the no is reversed the new no is formed 4 /3 times the original no find the original no

Answer 1

THANKS FOR THE QUESTION !

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LET,

THE FIRST TENS DIGIT IN THE NUMBER BE X

AND 2ND UNIT DIGIT BE Y

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SUM OF DIGITS IS 12 ....

SO

X + Y = 12

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THE NO. ACTUALLY IS

10X + Y

BECAUSE....

TAKE A NO. SUPPOSE 57

IT IS MADE BY 5*10 + 7

SO .....

NO. IS 10 * X + Y

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NOW IF IT IS REVERSED .....

MEANS 10Y + X.....

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THE NEW NO. IS 4/3 OF THE OLD NO..

MEAN S

10Y + X = 4/3 * 10X + Y

( 10 Y + X ) 3 = 4 ( 10X + Y )

30Y + 3X = 40X + 4Y

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ACTUALLY,

I THINK,

THE QUESTION HAS SOME PROBLEM

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IT CAN'T BE SOLVED ....

SORRY BUT I'VE TRIED....

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HOPE U WILL UNDERSTAND....^_^