Question

the sum of the digit of a two digit number is 10. Also twice the number is one more than the number obtained by reversing the digits. Find the numbers.
Please Help Meeeeeee

Answer 1

NOW ,

X=7
Y=3

So , required number = x + 10y = 7+10(3) = 7+30
= 37 .


Hence , required number is 37 .