Question

the sum of the digit of a two digit number is 10 the number is decreased by 36 if the digit are reversed find the number ​

Answer 1

Step-by-step explanation:

The sum of the digits of a two-digit number is 10.

let the ones digit is x then tens digit is 10-x

then the no is 10(10-x)+x........original no

If the digits are reversed,

the no is 10x+(10-x)...........new no

the new number is 36 more than the original number.

so 10x+(10-x)=36+10(10-x)+x

or 9x+10=136-9x

or 18x=136-10=126

or x=7 is the ones digit

so the tens digit ig 10-7=3

so the original number is 37 .

Answer 2

Answer:

73

Step-by-step explanation:

let 2 digit no. be 10x+y

now x+y=10 (1)equ

and 10x+y-36=10y+x

9x-9y=36

x-y=4

from both equ we get

x=7

and y=3

Now ,the no. is 10x+y

=10×7+3

=70+3

=73