Question

The sum of the digit of a two digit number is 10 the number obtained by interchanging the digit exceed to the original number by 36 find the original number

Answer 1

The original no. is 37

Step-by-step explanation:

Let the no. at one's place be x

and no. at ten's place be y

therefore no. is (10y+x).

According to question,

x+y = 10

or, y=10-x ------- eq. 1

also,

10x+y = 10y + x + 36

9x = 9y + 36

or, 9x-9y=36

or, 9(x-y)=36

or, x-y=4

or, x=4+y

or, x=4+(10-x) [from eq.1]

or, x+x=4+10

or, 2x=14

or, x= 07

from eq. 1

y =10-x

or, y= 10-7=3

therefore no. = 10y+x=10×3+7=37.