Question

the sum of the digit of a two digit number is 11 if the number obtained by reversing the digit is 9 less than the original number .Find the original number​

Answer 1

Answer:

The number is: 10x+y

Where, x is ten's digit and y is unit's digit

Now, on reversing the digits, we get the number: 10y+x

Now, According to question,

10y+x=10x+y-9

10y-y+x-10x+9=0

9y-9x+9=0

9(y-x+1)=0

y-x= -1 ....... eq^1

Also, sum of digit is 11

i.e., x+y=11 ..... eq^2

Now, on solving eq1 and eq2

We get,

x= 6 and y=5

So,the original number

10x+y= 10×6+5= 65

Ans. The required number is 65.

Step-by-step explanation:

Answer 2

I hope this will help you