the sum of the digit of a two digit number is 11.if the number obtained by reversing the order of the digits is 9 less than the original number ,find the original number.
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Answered by
6
The sum of two Digit is 11 and "reversing the digit"
Given : 2 digit with a and b
a+b =11, 10a +b = 10b +a = 9
9a-9b =9, a-b =1,b=a -1 ,2a-1= 11
a=6 and b=5
Answer is 65 ..
Answered by
2
Let the tens digit be x
Let the units digit be 11- x
A/Q
10x+11-x=10(11-x)+x+9
=>9x+11=110-10x+x+9
=>9x+11=119-9x
=>9x+9x=119-11
=>18x=108
=>x=108/18
=>x=6
The original number is 65
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