Question

the sum of the digit of a two digit number is 11 if the tens digit is 5 less than the ones digit find the
number

Answer 1

let ones digit be x 
so tens digit will be x-5
so=
x+x-5=11
2x=16
x=8

so ones digit is 8
and tens digit is 8-5=3
so number is = 38

Answer 2

Let the unit and ten's digits be x and y.
As per the question,
x + y = 11
x - y = 5
By solving the above equations,
2x = 16
x = 8.
And, y = 3.
So, the number will be 38.

Hope you will find it helpful....