Question

the sum of the digit of a two digit number is 11 the number obtained by interchanging the digits exceeds the original number by 27 find the number

Answer 1

take digit at ones place be x and digit at tens place =11-x....then common formula of 2 digitno...

Answer 2

Answer:

The given “two-digit number” is found to be 47

Explanation:

Let the number in one’s place be x and the number in ten’s place be y such that the number is yx.

Given that x + y = 11

y = 11 – x

Thus the number  

= 10 y + x

= 10(11 – x) + x = 110 – 10x +x = 110 – 9x

After interchanging, the number becomes

= 10x + y

= 10(x) + (11 – x) = 11 + 9x

Given that after interchanging the number exceeds by 27.

11 + 9x = 110 – 9x + 27

9x + 9x = 110 – 11 + 27

18x = 126

x = 126/18

x = 7  

y = 11 - x = 11 – 7 = 4

y = 4

Therefore the number is 47.