the sum of the digit of a two digit number is 12 if the new number formed by reversing the digit is greater than the original number by 54 find the original number check your solution
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Step-by-step explanation:
original number = 10x+y
reversing number = 10y+x
y+x=12
10y+x= 10x+y+54
9y-9x=54
y-x=6
y+x=12
y-x=6
subtract
2x=6
x=3, y =9
number =39
reversing number =93
93-39=54
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