Question

the sum of the digit of a two digit number is 12 if the new number formed reversin the digit is greater than the original number by 54 find the original number check your solution

Answer 1

Answer:

Step-by-step explanation:

Given sum of the digits is 12

Let the digits in ones place be x

Hence the digit in tens place is (12 – x)

The original number = 10(12 – x) + x = 120 – 9x

Number formed by reversing the digits = 10x + (12 – x)  =  9x + 12

Given that number formed by reversing the digits is 54 greater than the original number.

⇒ 9x + 12 = (120 – 9x) + 54 = 174 – 9x

⇒ 18x = 174 – 12 = 162

∴ x = 9

The original number = 120 – 9x = 120 – 9(9) = 39