Question

the sum of the digit of a two digit number is 12 in the new number formed by reversing the digit is greater than the original number by 54 find the original number check your solution​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

39

Step-by-step explanation:

let's represent the number as 10×a+b

and number reversed as 10×b+a

we know that,

a+b=12-------------(1)

and,

10a+b=10a+b+54------------(2)

so,

9b-9a= 54

9(b-a)=54

b-a =6 ----------(3)

and in (1) and (3)

we eliminate a,

2(b)=18

b = 9

from (1),

a+b= 12

a+9=12

a=3

so the number is 10a+b= 39