Question

the sum of the digit of a two digit number is 12 the given number exceeds the number obtained by interchanging the digit by 36 find the given number​

Answer 1

Let,

sum of the digit =x+y _ 1 equation

interchanging no.=(10x+y)-(10y+x)=36

A/Q,

(10x+y)-(10x+y)=36

10x+y-10x-10y=36

9x-9y =36

9(x-y)=36

(x-y)=36/9

=(x-y)=4 _ 2 equation

Adding equation 1 and 2

x+y=12

+ x-y=4

=2x=16

:x=16/2=8

:x=8

Putting the value of x

x+y=12

8+y=12

: :y=12-8

=4

::::10x+y

10×8+4

80+4

= answer

Answer 2

Answer:

$\huge\star{\red{Q}{uestion}}\star\:$

Sum of the digits of a two-digit number is 12. The given number exceeds the number obtained by interchanging the digits by 36. Find the given

number.

$\huge\star{\red {A}{nswer}}\star\:$

$\huge\underline {Let,}$

The tens digit of the required number be x

and the units digit be y

\huge\underline {Then,}

Then,

x + y = 12 ......... eq. (1)

Required number = (10x + y)

Number obtained on reversing the digits = (10y + x)

$\huge\underline {Therefore,}$

(10y + x) - (10x + y) = 18

9y - 9x = 18

x - y = 12 ......... eq. (2)<br>

On adding eq. (1) and eq. (2)

$\huge\underline {We\: get}$

x + y + y - x = 12 +2

2y = 14

y = 2

$\huge\underline {Therefore}$

x = 5

Hence, the required number is 57

$\huge\green { Hope\: this\: helps\: you}$