the sum of the digit of a two digit number is 12 the number obtained by interchanging its digits exceeds and given number by 18 find the numbers
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Let the no. be 10x + y
x + y = 12 eq1
10y + x = 10x + y + 18
9x - 9y = -18
x - y = -2 eq2
Solve eq1 and eq2
2x = 10
x = 5
put value of x in eq1
5 + y = 12
y = 7
Hence no. is 10x + y
10 × 5 + 7
57
Thanks
x + y = 12 eq1
10y + x = 10x + y + 18
9x - 9y = -18
x - y = -2 eq2
Solve eq1 and eq2
2x = 10
x = 5
put value of x in eq1
5 + y = 12
y = 7
Hence no. is 10x + y
10 × 5 + 7
57
Thanks
nilukrantijhap7zxll:
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