The sum of the digit of a two digit number is 12. the number obtained by interchanging its digits exceeds the given number by 18. find the number
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Step-by-step explanation:
let the no be X,y
two digit no 10x+y........ Reversed no=10y+X
------->
X+y=12
y=12-x ..........................(1)
A.T.Q= 10y+X = 18+10x+y
10y-y+x-10x =18
9y-9x =18
y-x =2.....................(2)
value of y in 1st eqn.
y-x =2
12-x-x=2
12-2x=2
10=2x
X=5
y=12-x
=7
So, the two digit no. is
10x+y=10*5+7
57
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