Question

The sum of the digit of a two digit number is 12. the number obtained by interchanging its digits exceeds the given number by 18. find the number

Answer 1

Step-by-step explanation:

let the no be X,y

two digit no 10x+y........ Reversed no=10y+X

------->

X+y=12

y=12-x ..........................(1)

A.T.Q= 10y+X = 18+10x+y

10y-y+x-10x =18

9y-9x =18

y-x =2.....................(2)

value of y in 1st eqn.

y-x =2

12-x-x=2

12-2x=2

10=2x

X=5

y=12-x

=7

So, the two digit no. is

10x+y=10*5+7

57