Question

the sum of the digit of a two digit number is 13 the number formed by interchanging the digits is 45 more than the original number find the original number
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Answer 1

Answer:

Let the ten's place digit be x & one's place digit be y respectively.

A/q

∴ Putting the value of of y in equation (1),we get;

Thus,

The original number = 10x + y

The original number = 10(4) + 9

The original number = 40 + 9

The original number = 49

Step-by-step explanation:

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Answer 2

Answer:

94

Step-by-step explanation:

let the digits be x and y

and the original no. be 10x+y

given,

x+y=13 ---------(1)

also given,

10y+x=45+10x+y

or

9y=45+9x

or

9y-9x=45

diving this by 9 we get

x-y=5---------(2)

from (1) and (2), we get,

x+y=13

or x=13-y

putting value of x in (2)

x-y=5

(13-y)-y=5

-2y= 5-13

-2y=-8

or

2y= 8

y=4

putting value of y in (1)

x+y=13

x+4=13

x=13-4

x=9

original no.=

10x+y

i.e.

10×9+4=

94

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