the sum of the digit of a two digit number is 13 the number obtained by interchanging it's digits exceeds the given number by 9. find the number?
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X+Y=13 ......(1) X+10Y=22......(2) By subtracting 1&2 We get X+10Y=22 -X- Y=-13 We get 9Y=9 Y=1 Substituting Y in 1 X+1=13 X=13-1 X=12
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