Question

the sum of the digit of a two digit number is 15. the number obtained by reversing the digit exist the given number by 9. find the number.​

Answer 1

Answer:

10x + y = 15

A/q,

10y + x = 10x + y + 9

9y - 9x = 9

y - x = 1

Now,

Answer 2

Answer:

The number is 87.

Step-by-step explanation:

Let's assume the unit digit as x.

and the tens digit be 15-x.

[As both the digits sums 15]

{ As we know that any two digit number can be written in the form of 10a + b }

so,

by letting them as x and 15-x.

We got a number i.e 10(15-x)+x

Than its reversed form will be -

10(x) + 15-x.

Here, in the question it is given that - The reversed number is 9 more than the original.

So,

we got an equation by this all -

10(15-x)+x +9= (10(x)+15-x )

141 - 9x= 10x + 15

150 - 9x = 9x + 24

141 - 15 = 9x + 9x

126 = 18x

7 = x

Here, the value of x is 7. {Unit digit}

So, tens digit which is 15-x comes to be 8.

So the number is 87.

and reversed number is 78.