the sum of the digit of a two digit number is 15 the number obtained by interchanging its digit exceeds the given number by 9 find the original number.
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Let the number be xy. Given,the sum of the digits of a two digit number is 15. x+y = 15 ...(1) Also, if the digits are interchanged the result exceeds the original number by 9. 10y+x=10x+y+9 10y+x-10x-y=9 9y-9x=9 y-x=1..(2) (1)+(2) => 2y = 16 y = 16/2 = 8 (1) => x+8=15 x=15-8=7 Therefore the given number is 78 HOPE , IT HELPS. FOLLOW ME.
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