The sum of the digit of a two digit number is 3 be subtracted 9 from the number the digits are interchanged find the original number
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Answered by
2
X+Y=3
10x+y-9=10y+x
By solving these equation we get x=2
Y=1
21 IS THE ANSWER
10x+y-9=10y+x
By solving these equation we get x=2
Y=1
21 IS THE ANSWER
Answered by
1
Let the two digit number be XY.
Here X, Y are digits.
According to the question,
X + Y = 3. ..... (1)
The number XY is actually 10X + Y because X is the tens digit and Y is the ones digit.
Subtracting 9 from the number gives the number with reversed digits.
So,
10X + Y - 9 = 10Y + X
9X - 9Y = 9
X - Y = 1. ..... (2)
In the above equation 10Y + X is the reversed number i.e. YX.
Solving (1) and (2), we get
X=2, Y =1
Therefore, the original number is 21.
Here X, Y are digits.
According to the question,
X + Y = 3. ..... (1)
The number XY is actually 10X + Y because X is the tens digit and Y is the ones digit.
Subtracting 9 from the number gives the number with reversed digits.
So,
10X + Y - 9 = 10Y + X
9X - 9Y = 9
X - Y = 1. ..... (2)
In the above equation 10Y + X is the reversed number i.e. YX.
Solving (1) and (2), we get
X=2, Y =1
Therefore, the original number is 21.
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