the sum of the digit of a two digit number is 7 if the digits are reversed the new number increased by 3 equal equals 4 times the original number find the original number
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here is ur answer buddy
let the ones digit of the number be y and tens be x
original number=10x+y
by given data,
x+y=7=>(1)
reversed number=10y+x
by given data ,
10y+x+3=4{10x+y}
=>10y+x+3=40x+4y
=>39x-6y=3
=>13x-2y=1=>(2)
(1)×2=2x+2y=14
(2)×1=13x-2y=1
15x=15
x=1
x+y=7
1+y=7
y=6
so the original number is 16
hope it helps
let the ones digit of the number be y and tens be x
original number=10x+y
by given data,
x+y=7=>(1)
reversed number=10y+x
by given data ,
10y+x+3=4{10x+y}
=>10y+x+3=40x+4y
=>39x-6y=3
=>13x-2y=1=>(2)
(1)×2=2x+2y=14
(2)×1=13x-2y=1
15x=15
x=1
x+y=7
1+y=7
y=6
so the original number is 16
hope it helps
Answered by
0
here is the answer hope it will help you
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