Question

The sum of the digit of a two - digit number is 7. If the digit are reversed, the new number increase by 3 equals 4 times the orginal number. find the orginal number.

Answer 1

as every no. has a standard form
for eg- 27=20+7=2*10+7
let the two digit no. be 10x+y
x+y=7. eq-1
reversing the digits , no. = 10y+x.
(for eg - reverse of 20+7=70+2)
so ,
10y+x+3=4(10x+y)
10y+x+3=40x+4y
10y-4y=40x-x-3
6y=39x-3
3*2*y=3*(13x-1)
2y=13x-1
put value of y =7-x in equation formed
2*(7-x)=13x-1
14-2x=13x-1
14+1=13x+2x
15=15x
x=1
put value of x in eq-1 , we get
y=7-1=6
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